28 plausibly. There are an infinite number of possibilities. If we assume all angles are equal, it narrows the field.
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Wrong answer.
The interior angles of a 30 sided polygon sum to (30 - 2)*180 = 5040 degrees. And you do not need to assume that the angles are equal. They can even be reflex angles.
sum interior angles = (number of sides - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 5040° ÷ 180° + 2 = 30
Any angle between 0 and 360 degrees (except 180 degrees!).
The sum of the interior angles of a 30-gon is (30-2)*180 = 5040 degrees. So each interior angle of a 30-gon is 5040/30 = 168 degrees.
1008
7! = 7 × 6 × 5 × ... × 2 × 1 = 5040
A polygon with 5040 interior angles has 5041 sides. The formula for the number of interior angles in a polygon is given by ( n ), where ( n ) is the number of sides. Since each polygon has as many interior angles as it has sides, a polygon with 5040 interior angles must have 5041 sides.
It has 30 sides
sum interior angles = (number of sides - 2) × 180° → number of sides = sum interior angles ÷ 180° + 2 = 5040° ÷ 180° + 2 = 30
30 sides
It will have 30 sides.
It is: (5040+360)/180 = 30 sides
They add up to 5040 degrees
The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 30 sides, the calculation would be ( (30 - 2) \times 180^\circ = 28 \times 180^\circ = 5040^\circ ). Therefore, the sum of the interior angles of a 30-sided polygon is 5040 degrees.
5040/180 + 2 = 30 The polygon would therefore have 30 sides.
sum_interior_angles = (number_of_sides - 2) x 180o ⇒ number_of_sides = sum_interior_angles ÷ 180o + 2 = 5040o ÷ 180o + 2 = 30
A 30 sided polygon
Any angle between 0 and 360 degrees (except 180 degrees!).