If the interior angle measures 1440 you have a serious problem.
If the sum of the interior angles is 1440, then the question can be answered as follows:
The sum of the interior angles of a n-gon is (n-2)*180 degrees
So (n-2)*180 = 1440
So that n-2 = 8 and so n = 10
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
It will have 360/10 = 36 sides
The method of finding the sum of the interior angles of a polygon is by multiplying the (number of sides)-2 by 180, so the sum of the interior angle measures in a 25-sided polygon would be 23*180, or 4140 degrees.
Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.
The polygon with the largest interior angle is a regular polygon, specifically a regular polygon with the greatest number of sides. In a regular polygon, all interior angles are equal, and the formula for calculating the interior angle of a regular polygon is (n-2) * 180 / n, where n is the number of sides. As the number of sides increases, the interior angle also increases. Therefore, a regular polygon with a very large number of sides will have the largest interior angle.
A polygon with interior angle measures of 108 would be a pentagon
The polygon would have 10 sides.
If each interior angle measures 174 degrees then it will have 60 sides
51 sides
8
7
6
15
The polygon will have 12 equal sides and each interior angle measures 150 degrees.
128.57 degrees
If each interior angle measures 176 degrees then it will have 90 sides
If each interior angle measures 170 then it will have 36 sides