There are 3 significant figures in '4.50g'
There are four significant figures in 33050. The trailing zero is not significant because there is no decimal. There would be five significant figures in 33050. If we were to remove the last zero in the number, we would alter the value of the number. Had the number been 3305.0, then there would have been four significant digits.
4
There are 4 significant digits
grams
302.05 grams
302.05 grams
5
There are 4 significant figures in this problem.
4 of them.
five. 30.002
The significant figures are the ones which convey meaningful information about the measurement beyond the magnitude. Saying that a sample weighs .0000039 grams is better stated as 3.9 x 10^-6 grams or perhaps 3.9 micrograms. That's two significant figures. All the zeroes are not significant.
I would use grams because grams would give you more significant figures for the measurement than kilograms
The rule when rounding off numbers is "If the first figure to be discarded is 5 or more then the previous figure is increased by 1". When 16490 is rounded off to 2 significant figures then the first figure to be discarded is 4. As this is less than 5 then the previous figure (6) is not increased by 1. 16490 to 2 significant figures is 16000.
There would be five. The only time you do not count figures as significant is if they are zeroes behind a decimal, but before any other figure. Ex/ 0.000501 only has three significant figures, while 1.000501 has seven.
5 significant figures.
There are 3 significant figures in '4.50g'