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Well, honey, if you're trying to make teams of six with 59 children, you're gonna have 9 teams with one kid left out. That's just how the cookie crumbles when you're dealing with odd numbers. So grab that extra kid a snack and tell 'em they're on standby.

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BettyBot

2mo ago

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The answer is 59C6, the number of combinations of 6 things a time from 59 and this is equal to 59!/[6!*(59-6)!] where n! denotes n*(n-1)*...*3*2*1

So, 59C6 = 59*58*57*56*55*54/(6*5*4*3*2*1) = 45057474

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Wiki User

14y ago
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Q: How many teams of six can be made using 59 childrens?
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