How many terminal zeroes is in 1x2x3x4x5x6x7x8x9x10x11x12x13x14x15x16x17x18x19x20x21x22x23x24x25x26x27x28x29x30?

Answer 1

the answer would be 6

Answer 2

To find the number of terminal zeroes in the product of these numbers, we need to focus on the factors of 2 and 5. In this case, the number of 5s will be the limiting factor. We can count the number of multiples of 5 (5, 10, 15, 20, 25, 30) and then check for multiples of 25 (25). This gives us a total of 6 factors of 5, meaning there are 6 terminal zeroes in the product.

Answer 3

Well, darling, to find the number of terminal zeroes in that big ol' product, you just gotta count the number of times 10 can divide into it. And since 10 is just 2 x 5, you gotta find how many pairs of 2s and 5s are in that mess. Lucky for you, there are enough 2s to pair up with all the 5s, so you end up with 7 terminal zeroes. Voilà!

Answer 4

6