39 times.
3 times
19 with remainder 3.
3 goes into 353 117 times with 2 remaining 353 - 2 = 351 = 3 x 117
13 times 9, or 39 times 3 will give you 117.
Yes. 273 is evenly divisible by three.
A:117
Well the factors of 117 are: 1, 3, 9, 13, 39, and 117 itself. Therefore: 1x117 = 117 3x39 = 117 9x13 = 117
117 as a product of primes is 3 times 3 times 13. 65 is 5 times 13. Both will divide every number that is a product of 3 times 3 times 5 times 13 and any other integer, i.e., every product of 585, including 585, 1170, 1755, etc. Of course this includes 65 times 117 or 7605. The smallest number that both divide is 585.
1, 3, 9, 13, 39, 117.
3 times
1, 3, 9, 13, 39, 117.