1339
913 -426 Since the 6 is larger than the 3 and the 2 is larger than the 1, you will have to regroup two times.
To subtract 316 from 624, you need to regroup twice. Start by subtracting 6 from 4 in the ones place, which requires regrouping from the tens place. Then, subtract 1 from 2 in the tens place, which also requires regrouping from the hundreds place. Finally, subtract 3 from 5 in the hundreds place to get the final result of 308.
98. Set your problem up as a long division problem or estimate that 3 will go into 300, 100 times and 294 is two times less than that.
The division problem that equals 9 is 81 ÷ 9 = 9. This is because when you divide 81 by 9, you are essentially asking how many times 9 can fit into 81, which is 9 times. Therefore, the answer to the division problem that equals 9 is 9.
Well friend, to find out how many times 30 goes into 450, we simply divide 450 by 30. When we do that, we see that 30 goes into 450 a total of 15 times. Isn't that just a happy little math problem?
913 -426 Since the 6 is larger than the 3 and the 2 is larger than the 1, you will have to regroup two times.
Exactly 35 times
To subtract 316 from 624, you need to regroup twice. Start by subtracting 6 from 4 in the ones place, which requires regrouping from the tens place. Then, subtract 1 from 2 in the tens place, which also requires regrouping from the hundreds place. Finally, subtract 3 from 5 in the hundreds place to get the final result of 308.
If you have to have at least one group of each, there are four.
I have many, many times with no problem
It's not my problem 😝
Got the problem many times "ghost app" and sometimes can't print anything.
Yes, no problem I did it many times
98. Set your problem up as a long division problem or estimate that 3 will go into 300, 100 times and 294 is two times less than that.
The word "quotient" comes from the Latin quotiens which means "how many times" and indicates how many times a number goes into another.
Becuase many times it is hard to deal with a problem, and drugs masks the problem.
2