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330 ways. Once we know he must answer the last question, the issue is really one of choosing 4 questions from the first 11 questions on the exam. There are 11 ways to choose the first question, 10 ways to choose the second, 9 ways to choose the third, and 8 ways to choose the fourth, so that would be 11*10*9*8... but the order of the questions doesn't matter. So we divide by the number of ways to rearrange the 4 questions (4*3*2*1=24), to get 330.

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16y ago

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Anonymous

4y ago
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Q: How many ways can a student select five questions from an exam containing 12 questions if he must answer the last question?
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