with a knife... lol... sorry couldn't help it
25 and 5 but there are more ways that equal to 125
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
Yes you can, but you have to use zig zag lines. Using straight lines there are only four ways to divide a square into two equal parts (along the lines of symmetry).
9
three
Only once, there will only be eights parts however you divide it.
with a knife... lol... sorry couldn't help it
Oh, dude, you can divide 20 into equal groups in so many ways! Like, you could do 4 groups of 5, 5 groups of 4, 10 groups of 2, or even 20 groups of 1. It's like a math buffet, pick your favorite combo!
6 and 6
Not counting negative numbers (which would give you an infinite number of ways of adding numbers together to equal 10), there are 6 different ways (permutations) of adding numbers together to equal 10. 0 + 10 1 + 9 2 + 8 3 + 7 4 + 6 5 + 5
5
It is not possible
no
25 and 5 but there are more ways that equal to 125
the factors are 1, 2, 4, 8, 16, 32
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.