30
with a knife... lol... sorry couldn't help it
25 and 5 but there are more ways that equal to 125
To divide a class of 32 students into groups with equal numbers of students, you would need to find the factors of 32. The factors of 32 are 1, 2, 4, 8, 16, and 32. Therefore, you can divide the class into 1 group of 32 students, 2 groups of 16 students, 4 groups of 8 students, 8 groups of 4 students, 16 groups of 2 students, or 32 groups of 1 student. So, there are 6 ways to divide the class into groups with equal numbers of students.
Yes you can, but you have to use zig zag lines. Using straight lines there are only four ways to divide a square into two equal parts (along the lines of symmetry).
9
three
Only once, there will only be eights parts however you divide it.
with a knife... lol... sorry couldn't help it
6 and 6
Not counting negative numbers (which would give you an infinite number of ways of adding numbers together to equal 10), there are 6 different ways (permutations) of adding numbers together to equal 10. 0 + 10 1 + 9 2 + 8 3 + 7 4 + 6 5 + 5
5
To determine how many ways you can divide the number 25, you can consider it in terms of its partitions. The number of partitions of 25, which refers to the ways of expressing 25 as a sum of positive integers, is 1958. Each partition represents a unique way to divide the number. This count includes different arrangements of the same numbers but does not consider the order of the summands.
It is not possible
no
25 and 5 but there are more ways that equal to 125
the factors are 1, 2, 4, 8, 16, 32
4p3*3p1 equal to 72 ways