600 US gallons = 138,600 cubic inches = 80.208333... cubic feet = 2.9707 cubic yards. (rounded)
1 yd³ = 201.97 gallons 403.94 ÷ 5 = 80.79 buckets
2640 pounds
i dont think you phrased your question correctly
32-33, five(5) gallon buckets in one cubic yard or sand. ur welcome :P
Too many to count.
To determine how many yards of sand are needed to fill a 275-gallon oil tank, first, convert gallons to cubic yards. There are 27 cubic feet in a cubic yard and 7.48 gallons in a cubic foot. Thus, 275 gallons is approximately 37 cubic feet (275 ÷ 7.48). Dividing by 27 yields about 1.37 cubic yards. Therefore, you would need approximately 1.37 yards of sand to fill a 275-gallon oil tank.
1 yd³ = 201.97 gallons 403.94 ÷ 5 = 80.79 buckets
.21 yards of sand will fill an area 115 inches by 67 inches to a depth of 2.5 inches.
12 sq yds
2640 pounds
50 x 5 x 0.33333r = 83 cubic yards
i dont think you phrased your question correctly
a gallon is 0.1337 cu ft, so 5 gallons is5 x .1337 = .668 cu ft5 cubic yards is 5 x 27 = 135 cubic feet135/.668 = 202 5-gallon pails
If it's a rectangular pool it will be about 3.7 yards. If oval, a little less.
Well, darling, a gallon of sand weighs approximately 12-15 pounds, so a 3-gallon bucket could hold around 36-45 pounds of sand. But let's be real, who's really out here measuring sand by the pound when you can just fill up the darn bucket and call it a day?
You need 8 yards of sand that is 16 foot wide and 2 inches deep which is a volume of 8 x 16/3 x 2/36 ~= 2.37 cubic yards of sand.
to build a volleyball court you will need about 3 or 4 yards of sand