The first digit can range from 0 to 2, so that's three potential zeros.
The second digit can be any number from 0 to 9, so it's always one zero.
The third digit can also be any number from 0 to 9, again resulting in one zero.
The fourth digit, representing tens of minutes, can be any number from 0 to 5, so that's five zeros.
The fifth digit, representing minutes, can be any number from 0 to 9, so it's one zero.
Adding these up, we get 3 + 1 + 1 + 5 + 1 = 11 zeros.
36 times
101
36 times. Hint: Seven, eight and nine can all be discarded.
An hour has 60 min. Assuming the clock has only the hour and minute displayed, every hour 1 would appear at 1, 11,12,13,14,15,16,17,18,19,10,21,31,41,51. Counting 11 as once there are 15 1s in an hour. In the 24 hours, only 0,2,3,4,5,6,7,8,9,22,23 have no 1 s in them. Therefore 1 aooears 165 times in those times. As for hours 1,10,11,12,13,14,15,16,17,18,19,21, there is always a 1 in the clock. This makes 1 appear 12*60 times which is 720 times. Therefore in total, 1 appears 885 times in a digital 24 hour clock.
The minute hand of a clock turns about 360 degrees each hour.
57
There are exactly 114 palindromes on a digital clock in a 24 hour period. I was asked to do this problem for homework and so theres your answer.
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There are 93 such events.
On an analog clock with a 12-hour face: 44 times. On a digital clock: zero. (No needles.)
36 times
i think its 17
36 times
Four.
The numbers of a clock are always in sequential order
Clocks have 0, 2 or 3 hands: 0 (digital clocks), 2 (hour and minute), 3 (hour, minute and second).
101