Wiki User
∙ 11y ago50 ml
Wiki User
∙ 11y agoAnonymous
50ml
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
.36 lbs
milli is metric for 1/1000. therefore there are 1000 millileters in a Liter
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
1000
143
50 Liters of the 60% solution.
Weigh 60 grams of Glacial Acetic acid into a 1 liter volumetric flask. Make up to the 1 liter mark with distilled water. There is now a 6% (w/v) solution.
684 ml
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
Add 10 g to a volumetric flask and make up to the 1 liter mark.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
2%
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
what percent of 63 is 9