0.25 mg
0.5 mg
.25 mg
1 mg
.25 mg
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg
This would depend on the specific sample and its stability. Without additional information, it is not possible to determine how much of the sample would remain unchanged after two hours.
After 132 hours, 1/4 of the initial sample of 10 Ci of Mo-99 would remain. Since the half-life is 66 hours, after 66 hours half of the sample would remain (5 Ci), and after another 66 hours (totaling 132 hours), half of that remaining amount would be left.
1 mg
1mg
0.25
1 mg
0.5 mg
1 mg
.25 mg
1 mg
To determine how much of a 100 gram sample would remain unchanged after 2 hours, it is necessary to know the specific decay rate or change process of the sample. For example, if the sample undergoes a decay process with a known half-life, you can calculate the remaining amount using the formula for exponential decay. Without this information, it's impossible to provide an exact answer. In general, if no decay occurs, the entire 100 grams would remain unchanged.
2.5