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The question can be rewritten as the following equation:

(20%x + 60%100)/(100+x) = 30%

Where x is the amount of 20% copper you need to add.

This equation can be solved by first multiplying both sides by (100+x) to get:

20%x + 60%100 = 30%100 + 30%x

Now 30%100 can be subtracted from both sides

20%x + 30%100 = 30%x

Now 20%x can be subtracted from both sides

30%100 = 10%x

Now both sides can be divided by 10%

300 = x

Thus you need to add 300 ounces of 20% copper alloy in order to get an alloy that totals 30% copper.

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Q: How much of an alloy that is 20 percent copper should be mixed with 100 ounces of an allo that is 60 percent copper in order to get an alloy that is 30 percent copper?
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