4 x 30 = 120
4 x 31 = 124
4 x 32 = 128
4 x 33 = 132
135 - 132 = 3
Answer: 33 with 3 remaining
15
135 goes into 256 1 time with a remainder of 121.
45 times.
16 with 7 remaining 135 - 7 = 128 = 8 x 16
7, remainder 2
0.75
8 goes into 135 , 16 time and .875 remainder
The numbers are 1 and 3 with no remainders
1 and 7 will go into both numbers evenly with no remainders
9 with 9 remaining 144 - 9 = 135 = 15 x 9
no, there would be absolutely no place to put them in your decimal.
One and two will go into both numbers evenly leaving no remainders.