4 x 30 = 120
4 x 31 = 124
4 x 32 = 128
4 x 33 = 132
135 - 132 = 3
Answer: 33 with 3 remaining
15
135 goes into 256 1 time with a remainder of 121.
45 times.
16 with 7 remaining 135 - 7 = 128 = 8 x 16
7, remainder 2
0.75
8 goes into 135 , 16 time and .875 remainder
The numbers are 1 and 3 with no remainders
9 with 9 remaining 144 - 9 = 135 = 15 x 9
1 and 7 will go into both numbers evenly with no remainders
no, there would be absolutely no place to put them in your decimal.
One and two will go into both numbers evenly leaving no remainders.