4 litres
10 liters.
The way I would do this is to first determine the amount of alcohol and that would be 0.09 x 16 ml = 1.44 ml then I would ask myself (0.08 * x) = 1.44 Therefore to have an 8% solution we would have a total of 18 ml of solution (by solving the above equation), thus we would have to add 2 ml of water (18 ml - 16 ml).
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
The original solution has 3.6 quarts of antifreeze in it. The equation then becomes (3.6 + x)/(12 + x) = 0.40, where x is the amount of antifreeze added. X is then equal to 2.
The least number that can be added to 60 to obtain a perfect cube is 4. Add 4 to get 64 whose cube root is 4
10 liters.
40.8 grams
50 gallons @ 3% must be added.
684 ml
0.6 of a pint.
To determine the amount of 18% solution to add: Let x = volume of 18% solution to be added. 0.18x + 0.10(360) = 0.15(x + 360) Solving for x, you would need to add 75 ml of the 18% solution to the 360 ml of 10% solution to obtain a 15% solution.
4.2 quarts
2 gallons.
0.6
Dissolve 15 g salt in 100 mL water.
2%
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.