x2y4z6-121
Use the difference of two squares to factorise:-
(xy2z3-11)(xy2z3+11)
Yes. 11 is a prime number, and it is a factor of 121. Actually, it is the square root of 121, because 11 x 11 = 121, so it is the only factor of 121 besides 1 in addition to being a prime factor.
No
Well, darling, the exponential form of 121 is 11^2. That's right, 11 multiplied by itself equals 121. So next time someone asks you that question, you can impress them with your newfound knowledge. You're welcome.
11 is a common factor of 55 and 121.
11² or 11^2.
121^1 = 121. Any number with an exponent of 1 is equal to itself.
11 times 11 = 121
11 times 11 equals 121
You can choose the base to be any number (other than 0, -1 and 1) and calculate the appropriate exponent, or you can choose any exponent and calculate the appropriate base. For example, base 10: 121 = 10^2.08278537 (approx) Or exponent = 10: 121 = 1.615394266^10 (approx). I expect, though, that the answer that is required is 121 = 11^2.
12 = 121
11 is a factor of 11. It's also a factor of 121. So 11 must be the greatest factor that's common to both 11 and 121. If there were a greater one, then there would have to be a factor of 11 that's greater than 11, which would not be easy.
The prime factor of 7 is 7. The prime factor of 121 is 11.
The factor that is paired with 11 to get 121 is 11. Eleven times eleven is equal to 121. Another way to say this is 11 to the power of 2, which means 11 x 11.
The base could be 11 and the exponent 2, giving 112 But, it could equally be base = 14641, and exponent = 0.5, or base = 10, and exponent = 2.082785 (approx)
Yes. 11 is a prime number, and it is a factor of 121. Actually, it is the square root of 121, because 11 x 11 = 121, so it is the only factor of 121 besides 1 in addition to being a prime factor.
121 = 11 x 11
How about: 11*11 = 121