a small airplane flies in a straight line at a average speed of 150 km/hour .how long dose it take the plane to fly 250 km
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
20.40
First construct a right triangle with the information provided. The height would be 2 miles and the base of the triangle would be 5 miles. Use the trig function tan which would be the following tan (θ) = opposite / adjacent = 5 miles / 2miles θ = tan-1 (5/2) θ = 68.2o
No because you touch yourself at night.|_ 4 VV |_Just kidding. It does!Psyche!Actually, it does not because when your mother dropped you from 2 meters above the ground, you fell at a negative VELOCITY. Speed does not specify direction, and therefore can not be negative.
My answer is Pi/50 ms-1. My solution uses geometry rather than calculus though. First, the cirumference of the circle = 30(Pi)m, and the time for one rotation is 120s. Therefore the speed of the rider perpendicular to the 15m radius is (30(pi))/120 = (pi)/40 ms-1 We need the velocity in the vertical direction, where the velocity along the tangent to the circle is (pi)/40. Drawing the triangle which involves this tangent, and the vertical and horizontal components of the velocity, the law of similar triangles says that the angle to which the vertical velocity is the opposite is the same as that formed by the 15m radius, and the vertical line from the diameter of the wheel which is parallel to the ground, which will be 24-15=9m long. This angle is therefore cos-1(9/15). Moving now to the triangle of velocity components, where x is the required vertical velocity, we have: x = sin(cos-1(9/15))*((pi)/40) = (4/5)*(pi)/40 =(pi)/50 The above answer is off by an order of magnitude, since 30(pi)/120 = (pi)/4 m/s The correct answer is (4/5)*(pi)/4 = (pi)/5 m/s.
Actually, you AND the coin are travelling at the same velocity as the plane. Therefore, when you flip it up it will come straight back to you and not into the guy behind you...as long as your throw is straight up in the air, of course. This is called relative velocity: the coin is traveling at a horizontal velocity of zero RELATIVE TO THE PLANE, but it is travelling at 400km/h (or whatever the plane is travelling at) RELATIVE TO THE GROUND.
If the person sat on the train their velocity relative to the ground would be 95kph. But he/she is goind 3kph to oppose this. So 95-3 = 92 kph to the north is velocity of person relative to the ground.
Time ticks at different rates, determined by ones velocity through space, or proximity to a massive object. The difference in your time and mine, or that gps satellite and ground based clock make it relative.
Speed is the relative velocity of a body (such as an athlete) given a frame of reference (such as the ground).
because the ground is solid
In order to add its velocity to his own,and that way increase his ground speed
It is the rate of change in the person's position in the direction towards - or away from - the centre of the earth.
No. 'Airspeed' is the airplane's speed relative to the air. 'Headwind' and 'tailwind' ... in fact, 'wind' in any direction ... is the speed of the air relative to the ground, which the airplane doesn't feel. So 'wind' affects only the craft's groundspeed, not its airspeed.
Moving an airplane on the ground is called 'taxiing'
A parachute would help you float safely to the ground from an airplane.
Perhaps you mean terminal velocity. This is the maximum velocity reached by an object falling to the ground when the acceleration due to gravity is matched by the drag resistance of the air through which it is falling.
The velocity of a boat relative to the shore is also known as 'Speed over ground' can be established by two main methods.1. Speed over ground can be established as average speed over ground, by making two position fixes in the chart, using the compass bearings towards at least two shore objects in each of the fixes and writing down the time. The average speedAvSpeed = Distance covered (measured in the chart) / Time elapsed between the two fixes.A fix is a determination of the boat position using landmarks shown in the chart.2. Using a GPS (Global Positioning System). A modern GPS gives you the instant speed over the ground. Using the distance travelled (registered by the GPS) and the elapsed time (also recorded by the GPS) you can calculate the average speed over ground (average velocity relative to shore). Some GPS units can calculate this average speed, if you reset the distance travelled and time elapsed data on the GPS when you start your navigation.