a small airplane flies in a straight line at a average speed of 150 km/hour .how long dose it take the plane to fly 250 km
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
20.40
First construct a right triangle with the information provided. The height would be 2 miles and the base of the triangle would be 5 miles. Use the trig function tan which would be the following tan (θ) = opposite / adjacent = 5 miles / 2miles θ = tan-1 (5/2) θ = 68.2o
No because you touch yourself at night.|_ 4 VV |_Just kidding. It does!Psyche!Actually, it does not because when your mother dropped you from 2 meters above the ground, you fell at a negative VELOCITY. Speed does not specify direction, and therefore can not be negative.
My answer is Pi/50 ms-1. My solution uses geometry rather than calculus though. First, the cirumference of the circle = 30(Pi)m, and the time for one rotation is 120s. Therefore the speed of the rider perpendicular to the 15m radius is (30(pi))/120 = (pi)/40 ms-1 We need the velocity in the vertical direction, where the velocity along the tangent to the circle is (pi)/40. Drawing the triangle which involves this tangent, and the vertical and horizontal components of the velocity, the law of similar triangles says that the angle to which the vertical velocity is the opposite is the same as that formed by the 15m radius, and the vertical line from the diameter of the wheel which is parallel to the ground, which will be 24-15=9m long. This angle is therefore cos-1(9/15). Moving now to the triangle of velocity components, where x is the required vertical velocity, we have: x = sin(cos-1(9/15))*((pi)/40) = (4/5)*(pi)/40 =(pi)/50 The above answer is off by an order of magnitude, since 30(pi)/120 = (pi)/4 m/s The correct answer is (4/5)*(pi)/4 = (pi)/5 m/s.
If the person sat on the train their velocity relative to the ground would be 95kph. But he/she is goind 3kph to oppose this. So 95-3 = 92 kph to the north is velocity of person relative to the ground.
Actually, you AND the coin are travelling at the same velocity as the plane. Therefore, when you flip it up it will come straight back to you and not into the guy behind you...as long as your throw is straight up in the air, of course. This is called relative velocity: the coin is traveling at a horizontal velocity of zero RELATIVE TO THE PLANE, but it is travelling at 400km/h (or whatever the plane is travelling at) RELATIVE TO THE GROUND.
The velocity of a person relative to the ground depends on their speed and direction of movement. It is typically measured in meters per second (m/s) or kilometers per hour (km/h) and can be positive (moving forward) or negative (moving backward). This velocity is determined by the person's motion relative to the stationary ground.
Time ticks at different rates, determined by ones velocity through space, or proximity to a massive object. The difference in your time and mine, or that gps satellite and ground based clock make it relative.
Speed is the relative velocity of a body (such as an athlete) given a frame of reference (such as the ground).
because the ground is solid
In order to add its velocity to his own,and that way increase his ground speed
To someone on the airplane, the crate would appear to fall straight down due to its initial horizontal velocity matching the airplane's speed. To someone on the ground, the crate would follow a parabolic path because of gravity acting on it vertically while it moves horizontally due to its initial velocity.
No. 'Airspeed' is the airplane's speed relative to the air. 'Headwind' and 'tailwind' ... in fact, 'wind' in any direction ... is the speed of the air relative to the ground, which the airplane doesn't feel. So 'wind' affects only the craft's groundspeed, not its airspeed.
Relative to the bus, you are moving towards the back. If your walking speed is slower than the speed of the moving bus (which it usually will be) then your motion relative to a point on the ground will be moving in the direction of the moving bus, but slower by the speed at which you are walking.
Moving an airplane on the ground is called 'taxiing'
The resultant velocity of the plane relative to the ground can be calculated using vector addition. Given the plane's speed due north (100 km/h) and the crosswind speed (100 km/h westward), use the Pythagorean theorem to find the resultant velocity. The resultant velocity will be 141 km/h at an angle of 45 degrees west of north.