Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12
area of triangle =(1/2)(base)(height) 16=(1/2)(4)h h=8
34
area will get 4 times
its technically adding 2+2 which equals 2x2 answer: 4
If the base of a triangle is b and the height of the triangle is h, the area of the triangle is given by the formula: area = 0.5 x b x h.As such, in your case we have 28 = 0.5 x 4 x h, which means that h = 14.
Area = 1/2*base*height = 12 square units.
A=1/2 bh A=1/2 x 6 x 4 A= 3 x 4 A= 12
Equation of line: 3x-7y+4 = 0 Base of triangle: 4/3 Height of triangle: 4/7 Area of triangle: 0.5*4/3*4*7 = 8/21
No siree
The area of triangle is : 4.0
The information given is a classic example of the dimensions of a right angled triangle with a hypotenuse of 5cm, a base of 3cm and a height of 4cm. Area of a triangle = 1/2*base*height Area = 1/2*3*4 = 6 square centimetres
Such a triangle cannot exist. a = 4 3b = 4 so that b = 4/3 = 1.33.. so that a+b = 5.33... In any triangle, a+b > c Since that is not the case here, the three sides cannot form a triangle.
Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
If AC equals 6 and BD equals 4, then AB equals 5.
The area of triangle is : 12.0
It can be anything between zero and infinity, depending on the angle between AC and BC.