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If a car can accelerate from zero to 60 mph in 9 seconds how fast is traveling from a stop after moving 18 ft?
aceeleration = (initial + final) divide by time
so a= (0 + 60) divide by 9
a = 6.666666667 mile
18 feet = 0.00340909091 mile
s=ut + 0.5at2 s=displacement, u=initial speed, a=acceleration t=time
0.00340909091 mile = 0t +0.5(6.666666667)t2
t2 = 0.00340909091/0.5(6.666666667)
t2 =0.0454545455
t = 0.213200716
v=u+at v=final speed
v= 0 + 6.666666667(0.213200716)
v=1.42133811
so after moving 18ft the speed of the car = 1.42m/s2
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