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a/b=c/d

=>ad=bc

=>a =bc/d

b =ad/c

c =ad/b

d =bc/a

so if a+b=c+d is true

=> (bc/d)+(ad/c)=(ad/b)+(bc/a)

=> (bc2+ad2)/dc=(da2+cb2)/ab

=> ab(bc2+ad2)=dc(da2+cb2)

and since ad=bc,

=> ab(adc+add) =dc(ada+adc)

=> abadc+abadd =dcada + dcadc

=> abadc-dcadc =dcada-abadd

=> (ab-dc)adc =(dc-ab)add

ad cancels out

=> (ab-dc)c =(dc-ab)d

=> -(dc-ab)c =(dc-ab)d

=> -c = d

so there's your answer :)

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Q: If a over b equals c over d then is it possible that a plus b equals c plus d If not then give Mathematical Reason for that?
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