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perimeter is when you have a shape and then you have your area and that is what is in the middle of the shape and perimeter is the edge of the shape.
No the area is not always larger than the perimeter. Ex. The area of a reectangle could be 4 feet. The width could be 4 while the length is 1. The perimeter total would be 10.
Any 2-dimensional shape can have a perimeter of 14 cm.
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If both dimensions are doubled then the area is quadrupled. This is true of any geometric shape.
It is multiplied by nine.
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If one dimension of a 3-dimensional shape is doubled, the volume increases by 21 = 2. If two dimensions of a 3-dimensional shape are doubled, the volume increases by 22 = 4. If all three dimensions of a 3-D shape are doubled, the volume increases by 23 = 8.
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To find the perimeter of a shape with an area of 480 square feet, you first need to know the shape's dimensions. For example, if you consider a rectangle, the area can be calculated as length multiplied by width (A = length × width). If you take a rectangle with dimensions of 20 feet by 24 feet, the perimeter would be 2(length + width) = 2(20 + 24) = 88 feet. Other shapes will yield different perimeters for the same area depending on their dimensions.
The perimeter doesn't tell you the dimensions. It doesn't even tell you the shape.
The perimeter is the distance around a shape, If the dimensions given describe a rectangle with length of 8cm and width of 6cm, the perimeter would be 2(L + W), which means the length and width are added together and multiplied by 2. Hence. 8 + 6 = 14 X 2 = 28cm perimeter.
The perimeter is the distance around a shape, If the dimensions given describe a rectangle with length of 8cm and width of 6cm, the perimeter would be 2(L + W), which means the length and width are added together and multiplied by 2. Hence. 8 + 6 = 14 X 2 = 28cm perimeter.
To find the dimensions of a shape with an area of 49 and a perimeter of 28, we can assume it is a rectangle. Let the length be ( l ) and the width be ( w ). The area can be expressed as ( l \times w = 49 ) and the perimeter as ( 2l + 2w = 28 ). Solving these equations, we find that one possible set of dimensions is ( l = 7 ) and ( w = 7 ), indicating the shape is a square with sides of length 7.