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The way to solve this kind of problem is to calculate how much each animal eats in an hour, and add the fractions. (Of course, some assumptions are being made, mainly, that the lions eat at the same rate all the time.)

In an hour, the lion eats 1/2 sheep, the wolf 1/3 sheep, and the dog, 1/5 sheep. Adding the fraction:

1/2 + 1/3 + 1/5 = 15/30 + 10/30 + 6/30 = 31/30. The time it takes all together is the reciprocal of this: 30/31 of an hour, approximately 58 minutes.

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Q: If it takes a lion 2 hours to devour a sheep a wolf 3 hours to devour a sheep and a dog 5 hours to devour a sheep How long would it take to devour one sheep if they all ate at the same time?
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A lion could eat a sheep in 4 hours A leapord could eat one in 5 hours A bear could eat one in 6 hours How long would it take for all of them to devour a sheep if it were thrown among them?

Lion eats 1/4 sheep per hour.Leopard eats 1/5 sheep per hour.Bear eats 1/6 sheep per hour.Working together, they can eat (1/4) + (1/5) + (1/6) sheep per hour.(1/4) + (1/5) + (1/6) = (15/60) + (12/60) + (10/60) = 37/60 sheep per hour.60/37 hours per sheep = 1.6216 hours = 1hr 37min 17.84sec (rounded)


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Related questions

Lion takes 2 hours to eat a sheep wolf takes 3 hours dog takes 6 hours if all the 3 animals join together and eat the sheep how long will it take?

1 hour. the lion eats 1 sheep / 2 hours the wolf eats 1 sheep / 3 hours the dog eats 1 sheep / 6 hours add all of that together... 1/2 + 1/3 + 1/6 = 6 sheep / 6 hours = 1 sheep per hour


A lion could eat a sheep in 4 hours A leapord could eat one in 5 hours A bear could eat one in 6 hours How long would it take for all of them to devour a sheep if it were thrown among them?

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