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If sinA equals 1 by 3 evaluate cosA cosecA plus tanA secA?
Himanirana
SinA = 1/3 = Opposite/Hypotenuse
Therefore taking Opposite to be 1cm and Hypotenuse to be 3cm.
Therefore Adjacent side = Root of 32 - 12
= root 8
CosA = Adjacent/Hypotenuse = root8 / 3
CosecA = Hypotenuse/Opposite = 3/1
TanA = Opposite/Adjacent = 1 / root8
SecA = Hypotenuse/Adjacent = 3 / root8
Therefore,
(CosA.CosecA) + (TanA.SecA) = (root8 / 3 . 3 / 1) + (1 / root8 . 3 / root8)
= (root8) + (3 / 8)
= 2(root2) + (3 / 8)Wiki User
∙ 11y ago
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