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SinA = 1/3 = Opposite/Hypotenuse

Therefore taking Opposite to be 1cm and Hypotenuse to be 3cm.

Therefore Adjacent side = Root of 32 - 12

= root 8

CosA = Adjacent/Hypotenuse = root8 / 3

CosecA = Hypotenuse/Opposite = 3/1

TanA = Opposite/Adjacent = 1 / root8

SecA = Hypotenuse/Adjacent = 3 / root8

Therefore,

(CosA.CosecA) + (TanA.SecA) = (root8 / 3 . 3 / 1) + (1 / root8 . 3 / root8)

= (root8) + (3 / 8)

= 2(root2) + (3 / 8)
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Q: If sinA equals 1 by 3 evaluate cosA cosecA plus tanA secA?
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