I think you mean the roots are prime numbers.
Let the two roots be primes p and q
Then the equation factorises to (x - p)(x - q) = 0 which can be expanded to give:
x² - (p + q)x + pq = 0
Which comparing coefficients of the original gives:
a = p + q
2b = pq
as b is an integer, pq must be even,
→ at least one of p or q must be even
→ as they are both primes and at least one is even, it MUST be 2 as 2 is the ONLY even prime
Assume p is an even prime, ie p = 2
→ a = 2 + q
2b = 2q → b = q
→ a - b = (2 + q) - q = 2
(It doesn't matter if the other prime is even (2) or not as it cancels out from a - b.)
No it equals negative. (-)+(+)=(-)
No, it equals a positive. (+)+(+)=(+)
a positive a negative times a negative also equals a positive
Yes, it does. An equation is something that equates something to something else, by means of the 'equals' sign.
x=0
1. The only positive integer that equals 9 is 9.
The sum of two positive integers can never equal zero.
No. Two negative integers added together will never equal a positive integer. It is the product of two negative integers that is positive.
The sum of the first 40 even positive integers can be equal to 820.
-4
when you have a negative times a negative it will equal a positive but when you have a negative times a positive it will equal a negative no matter what!
No, that is not true.
Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.
it equals a positive.
Only when you divide or multiply.
2+2/-2+4
No it equals negative. (-)+(+)=(-)