one....
6
The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
If there are seven people, then the number of handshakes is 7*6/2 = 21
The answer is 21 handshakes because the first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. Therefore the answer is 21 handshakes.
45 Handshakes All Together
6
25 shakes
The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
If there are seven people, then the number of handshakes is 7*6/2 = 21
The answer is 21 handshakes because the first person shakes hands with the other 6 people. The second person shakes hands with 5 people because they already shook hands with the first person. The third person shakes hands with 4 people because they already shook hands with the first and second person. The fourth person shakes hands with 3 people because they already shook hands with the first, second, and third. The fifth person shakes hands with 2 people because they already shook hands with the first, second, third, and fourth person. The sixth person shakes hands with the seventh person because the rest have already shaken hands with them. The seventh person doesn't have anyone else to shake hands with. Therefore the answer is 21 handshakes.
105 ( First person shakes 14 different hands, second shakes 13 etc etc down to 14th shakes 1 hand. Sum of 1 to 14 = 105.)
The verb form for the noun 'handshaking' is to shake hands (shakes hands, shaking hands, shook hands), a verb-object combination.
45 Handshakes All Together
the first shakes 8 people's hands (remember, not his own), the second 7 (he doesn't shake the first one's hand), then the third shakes six, the fourth shakes 5, the fifth shakes 4, the sixth shakes 3, the seventh shakes 2, and the 8th shakes the 9ths hand so 8+7+6+5+4+3+2+1 = 36
Depends what you mean, if you mean if everyone shakes hands just once then N-1 handshakes are made. If you mean if everyone shakes hands with everyone else then the answer is (N-1)+(N-2)+....+2+1 (we dont include N as they're not going to shake their own hand, obviously) written as Σn-1i=1 i, this is a arithmetic progression and so the total number of handshakes will be equal to (1+(n-1))(n-1)/2
First person shakes hands 19 times, second person 18 etc, a total of 190.
36. Everybody shakes 8 hands but each shake counts for 2 people. So 9*8/2=36.