one leg is root300 which is close to 17.3 and the other is 2 times root300 close to 34.6
.The hypotenuse is twice as long as the shorter leg The longer leg is twice as long as the shorter leg.
A right triangle. * * * * * Not necessarily. All that can be said is that is is not an equilateral triangle. It can be isosceles or scalene. It can be acute angled, right angled or obtuse angled.
The hypotenuse of a right triangle is 26 feet long one leg of the triangle is 14 feet longer than the other leg find the lengths of the legs of the triangle? The best advise is to draw a right triangle with the base about twice as long as the height. Label the height x Label the base x+14 Label the hypotenuse 26 . Use Pythagorean Theorem Eq. #1..(Base)^2 + (Height)^2 = (Hypotenuse)^2 Substitute variables and length of hypotenuse into Eq. #1. (x)^2 + (x + 14)^2 = (26)^2 x^2 + x^2 +28x + 196 = 676 Combine like terms and move all to the left side. 2x^2 +28x - 480 = 0 This is a quadratic equation. Here is a web site for a quadratic equation solver. http://www.math.com/students/calculators/source/quadratic.htm I made a short cut to this site on my desk top, since I use it so often. I solved the quadratic by hand until I found this site. I do not need practice solving quadratic equations by hand. The 2 answers are 10 and -24. Well, I never saw a triangle with height = -24 feet long. Height = x = 10 ft. Base = x + 14 = 24 ft Check with Pythagorean Theorem 10^2 + 24^2 = 26^2 100 + 576 = 676 We're OK I find it interesting that though the -24 can not be used, thelong side = +24ft
Letting S represent the length of a side of an equilateral triangle having a height of 1 unit, then drawing a perpendicular from the mid point of a side to the opposite vertex creates a right triangle having sides 1, S, and ½S, with S being the hypotenuse of a right triangle. The square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the lengths of the other two sides; thus S2 = (H2 + (½)2S2) = 1 + ¼S2. Subtracting 1 from each side, S2 - 1 = ¼S2. Multiplying the terms on each side by 4, 4S2 - 4 = S2; subtracting S2 from each side, 3S2 - 4 = 0; adding 4 to each side, 3S2 = 4; dividing each side by 3, S2 = 4/3; Taking the square root of each side, S = 2/1.732 = 1.1547 The length of each side of an equilateral triangle is the product of 1.1547 x height. (Note: 1.1547 is twice the reciprocal of the square root of 3.) Example: if the height of an equilateral triangle is 30 cm, the length of each side will be 34.641cm (30 x 1.1547cm).
A regular hexagon
When two sides of a right triangle are 6 and 8, the triangle is similar to a 3-4-5 right triangle. Since 6 is twice 3 and 8 is twice 4, the hypotenuse has to be twice 5 or 10.
90 degrees. This is an isosceles right triangle, standing on its hypotenuse.
.The hypotenuse is twice as long as the shorter leg The longer leg is twice as long as the shorter leg.
Shorter leg = 1Longer leg = 2Hypotenuse = sqrt(5)Cosine of angle between the longer leg and the hypotenuse = 2 / sqrt(5) = 0.89443 (rounded)The angle is 26.565 degrees (rounded)
To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.
That will depend upon the statements of which none have been given about a right angle triangle.
A right triangle. * * * * * Not necessarily. All that can be said is that is is not an equilateral triangle. It can be isosceles or scalene. It can be acute angled, right angled or obtuse angled.
Draw a line joining the top vertex to the middle of the base. This divides the triangle into two right-angled triangles, which are congruent (both have the same side lengths and angles). Each right-angled triangle has a hypotenuse length of 34 cm (the hypotenuse is the side opposite the right angle). They also have a side which is the height of the triangle, 30 cm. By Pythagoras' theorem, the third side of each right-angled triangle is 16 cm long because 342 - 302 = 1156 - 900 = 256 = 162 The base of the isosceles triangle is twice that, so it's 32 cm long.
90, 60 and 30 degrees
34 Use the pythagorean equation for a right triangle let x be one leg of the triangle, so the hypotenuse would be 2x +2 , and the other leg is 30 so using the equation we get: x2 + 302 = (2x+2)2 x2+900 = 4x2+8x+4 Rearranging, we get 3x2+8x-896 = 0 Using the quadratic equation we can solve for x, x = {-b +/- SQRT(b2-4ac)}/2a x = {-8 +/- SQRT(82-4(3)(-896))}/2(3) x = 16, and -18.667 but we can eliminate the negative answer so the hypotenuse will be 2*(16) + 2 or 34
First of all, it is obviously a right triangle. Suppose the shortest leg (the one with the 60 and 90 degree angle) is xunits long. Then the other leg is x times (the square root of 3). The hypotenuse is just twice the length of the first leg (2x). With this triangle you are able to find the side lengths and the angles without using trigonometry.
You need the length of a side. Try sketching different size triangles with 30/60/90 degree angles - there's an infinite number of them. The length of the hypotenuse is the shortest side / sin30 or the third side / sin60. As sin 30 is 0.5 then the hypotenuse is twice the length of the shortest side (or the third side divided by ½root3 ).