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Designate the smaller number as s. From the statement of the problem, s + s +12 = 90; or 2s = 90 -12 = 78; s = 39

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Q: If the sum of two numbers is 90 and their difference is 12 what is the smaller number?

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The sum of the sum and difference gives twice the larger number 14 + 4 = 18 → the larger number is 18 ÷ 2 = 9 The difference of the sum and the difference gives twice the smaller number 14 - 4 = 10 → the smaller number is 10 ÷ 2 = 5 → The two numbers are 9 and 5.

If their difference is 25 then the larger number is the smaller number plus 25. Let the smaller number be x then the larger number is x + 25 → their sum is x + (x + 25) = 81 → 2x = 56 → x = 28 → the two numbers are 28 and 53.

18 and 6

the answer is of course 12

smaller no.14 larger 37

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212

The sum of the sum and difference gives twice the larger number 14 + 4 = 18 → the larger number is 18 ÷ 2 = 9 The difference of the sum and the difference gives twice the smaller number 14 - 4 = 10 → the smaller number is 10 ÷ 2 = 5 → The two numbers are 9 and 5.

To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.

If their difference is 25 then the larger number is the smaller number plus 25. Let the smaller number be x then the larger number is x + 25 → their sum is x + (x + 25) = 81 → 2x = 56 → x = 28 → the two numbers are 28 and 53.

18 and 6

The smaller number is (74-16)/2 = 58/2 = 29

No. Consider 0 and 1. Or negative numbers, whose sum produces a smaller number.

The smaller number is 4.

the answer is of course 12

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