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If there are 3000 books divided into 3 piles and the first pile has 10 more books than the second pile and the second has twice as many as the third how many books are in the third pile?
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Let x = third pile
First Pile = 2x + 10
Second Pile = 2x
Third Pile = x
(2x+10) + (2x) + (x) = 3000
2x + x + 2x + 10 = 3000
5x + 10 = 3000
5x = 3000 - 10
5x = 2990
x = 2990/5
x = 598
Therefore there are 598 books in the third pile. I'm sure you can figure out how to get how many books are in all other piles.
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