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If there were 49 matches in a year and you lost 4 for every 2 you won, you would win 16 or 17 matches. The exact number is only accurate in multiples of 6, so the 49th match could be a win or a loss.

Q: If there were 49 matches in a year and you lost 4 for every 2 you won how many would you win?

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There would still be 360o. But instead of the earth rotating 15o every hour it would only rotate 10o every hour.

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52/2 = 26

You would get two or three checks a month, depending on how many Fridays in that month. You would get 26 checks per year most years and sometimes get 27.

I am no sure what you mean by shape, but there are infinitely many different regular polygons, one for every positive integer, so I would think there must be infinitely many shapes.

Related questions

most of the time

randy orton has lost 52 matches and won 519 matches he has been in 572 matches ...amooolh...

randy orton has lost 52 matches and won 519 matches he has been in 572 matches.

Federer has lost 157 Singles Matches and 72 Doubles Matches.http://en.wikipedia.org/wiki/Roger_Federer

every time sehwag take ten matches.

6

10000000

This season 10 times.

111111 and 2222

If I am understanding your question properly, he has had way too many matches to determine how many times he actually lost.

LIKE 109

India has played a total of 721 One Day matches and won 349 out of them. Also we have played a total of 430 test matches. Out of which we have won 99 and lost 136