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If there are n people who shake hands with each other exactly once, it can be observed that there are n x (n-1) handshakes.
Since each handshake is counted twice here,we divide this by 2.
Therefore, total number of handshakes is n(n-1)/2.
In the given problem,
Given: Total handshakes =66
i.e n(n-1)/2=66
n2-n =132
n2-n-132=0
(n-12)(n+11)=0
n =12 or n= -11
As handshakes cannot be negative we discard 11 .
Therefore answer is , 12 people.
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If there 28 handshakes how many people are at the party?
29 People including You.
How many people are at a party with 741 handshakes if everyone shakes once?
371
If ten people are at a party and they all exchange handshakes how many hand shakes were exchanged?
If that happens you have to times ninexten and the answer would be 90 handshakes
If there are 8 people at a party and every person shakes hands with everyone else at the party how many handshakes will there be?
There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.
How many handshakes if 6 people?
If six people meet there are fifteen handshakes.
