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If there are n people who shake hands with each other exactly once, it can be observed that there are n x (n-1) handshakes.

Since each handshake is counted twice here,we divide this by 2.

Therefore, total number of handshakes is n(n-1)/2.

In the given problem,

Given: Total handshakes =66

i.e n(n-1)/2=66

n2-n =132

n2-n-132=0

(n-12)(n+11)=0

n =12 or n= -11

As handshakes cannot be negative we discard 11 .

Therefore answer is , 12 people.

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Q: If theres 66 handshakes how many people are at the party?
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