If two dice are thrown what is the probability theat neither one shows a three?

Answer 1

SAMPLE SPACE

{ (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of cases : 36 (from sample space )

Let E be the event where neither of the dice show 3

The number of favorable cases have been striked = 25

p(E) = 25 / 36