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Plane A travels due north at 150 mph for 2 hours, it will go 300 miles.

Plane B travels due west at 200 mph for 2 hours, it will go 400 miles.

Draw the two vectors and you will see that they make two sides of a right triangle. The distance between the two planes at the end of two hours is just the hypotenuse of this triangle.

You could use the Pythagorean theorem (c^2 = a^2 + b^2) to find the distance...or you could recognise that 300 and 400 are two of a pythagorean triplet (300, 400, 500) and the third number of this triplet is 500.

So, the planes will be 500 miles aprt at the end of two hours

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Q: If two planes leave the same airport at 100 PM how many miles apart will they be at 300 PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?
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If two planes leave the same airport at 1 o'clock PM how many miles apart will they be at 3 o'clock PM if one travels directly north at 150 mph and the other travels directly west at 200 mph?

One plane will be 300 miles (150 mph * 2hours ) north. The other plane will be 400 miles (200 mph * 2hours ) west. This makes a right triangle with sides of 300 and 400. If you know your right triangles, you will know that the hypotenuse will be 500 miles. (3-4-5 triangle) If not hypotenuse = √(3002+4002) = 500 miles They will be 500 miles apart.


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