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Q: If you go twice as fast will your stopping distance increase by twice or four times?
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As a vehicles speed increases what happens to stopping distance?

It increases faster than the speed increase ... approximately the square of the speed. So twice the speed results in 4 times the stopping distance.


As a vehicles speed increases it's stopping distance?

With increased speed, stopping distance increases.


Is it twice the stopping distance for a car in freezing conditions?

No - the stopping distance depends on the speed of the vehicle - it' not simply a case of 'doubling-up'.


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Assuming the distance between the two objects does not increase then the gravitational force will become 4 times as great.


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A car travels twice as fast as a second car. The faster car will take how much more distance to stop?

The stopping distance is not straightforward and depends on two factors: The time for a driver to react to a situation called the "thinking distance". The distance travelled in between the driver realising he needs to brake and actually braking and during which the car carries on moving. The distance taken to stop once the brakes are applied called the "braking distance". Both these factors combine to make the total stopping distance, which is not a linear scale. Thus going twice as fast does not simply double the distance. Thus without knowing what the speed of the slowest car is we can not tell you "how much more distance to stop" at 20 mph the distance is 40 feet (under ideal conditions). at 30, 75 feet at 40, 118 feet at 50, 175 feet at 60, 240 feet at 70, 315 feet


How do you find circumference if you have a radius of 15m?

Circumference (distance around) is equal to pi (3.14) times the diameter. Diameter (distance across a circle) is twice the radius (distance from center to edge. 2 x 15= diameter of 30. 30 times 3.14= 94.2 meters for the circumference.


Why does kinetic energy quadruple if speed doubles?

Work (which is a type of energy transfer) = force x distance.Look at the formulae for acceleration. The relevant formula in this case (simplified for the case that the initial speed is zero) is: Distance = (1/2) acceleration time squared Let's keep the acceleration constant. Note that this will also make the force constant. In this case, in twice the time your object will move four times the distance. Note that at constant acceleration, in twice the time you get twice the speed (assuming that you start at speed = 0). Combining all of the above, to get twice the speed, you need to apply the same acceleration (and therefore, the same force) over FOUR times the distance. As a result, the amount of work required to achieve this acceleration will also increase by a factor four. Or in general, it will scale with the square of the speed.


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