2 amperes (current = voltage/resistance)
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Just off the top of my head . . . -- 4 parallel line segments, with a separate line segment crossing all of them -- 5 line segments all hooked together at the same point in the center, like five spokes of a wagon wheel.
Oh, what a lovely question! In "One Mile of Ice" by Hugh Garner, there are two main conflicts that add depth to the story. The first conflict is the external struggle between the protagonist and the harsh winter elements as they try to survive in the unforgiving Canadian wilderness. The second conflict is the internal battle the protagonist faces as they grapple with their own fears, doubts, and limitations. These conflicts work together to create a rich and engaging narrative that keeps the reader hooked from start to finish.
The current will increase to a very large value
When a battery is hooked up to an open circuit, no current flows because the circuit is not complete. The voltage across the open circuit is equal to the battery voltage, but no electrical work is done since there is no flow of electrons. The energy stored in the battery remains as potential energy until a complete circuit is established.
Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ
Chemical energy in the battery is turned into electrical energy when the battery is hooked up to an electrical circuit.
Your question is confused. A galvanometer is an instrument, it is not hooked to an instrument. It is hooked to an electrical circuit of some kind, to measure how much electricity is flowing.
No, the battery is part of it's circuit. In fact nothing in the car will work without the battery.
You hooked up the batteries in Series whch pumped allot of current thur the circuit..which probably fried the voltage regulator and probably blew the diodes on your alternator. you can have the alternator tested at an auto parts store.. but I'd replace the voltage regulator ( if its not part of the alternator ) along wth the alternator.. gpawlak1@rochester.rr.com
Too much current was flowing which caused an overheating problem. Can be the battery has a dead cell, or you reversed the cables.
Because it is suppose to start if the battery is hooked up.
A battery doesn't make any watts by itself, it has to be hooked up to a load first. And even something as tiny as an AAA battery can put out some decent watts for a brief moment if hooked up to something that'll pull a lot of amps - like a short circuit.
If a component is hooked into a live circuit, it is likely that the component itself will be damaged.
You use an "amp gauge" to measure amps in an actual circuit. It is hooked in series with the load. It can be placed anywhere in the circuit as long as it is hooked in series. Mathematically, you have to know the resistance, or wattage and voltage of a circuit. Volts=amps*resistance or amps=volts/resistance, or resistance=volts/amps. Ohms law!