The numbers divisible by all five numbers must be multiples of the LCM (LCD) of the numbers,
which is 22 x 3 x 5 = 60.
There are 5 numbers: 240, 300, 360, 420, and 480.
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There is also a C program that can be used to find these:
#include <stdio.h>
void main()
{
for (int i=200;i<=500;++i)
if (!((i%6)(i%4)(i%5)(i%3)(i%2))) printf("%d ",i);
printf("\n");
}
2
456,256
There are 43 natural numbers between 200 and 500 that are divisible by seven.
I think the answer is: 66 numbers between 1 and 200 are divisible by 3. :) That's what I think the answer is.
Exclusively, meaning not including 200 and 500, there are 149 even (divisible by two) numbers between 200 and 500.
Not sure!
There are 80 such numbers.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
12. 13, if you count 200
There are 43 natural numbers between 200 and 500 that are divisible by seven.
There are 5 multiples of 18 between 200 and 300. (An even number divisible by 9 is any number divisible by 18).
I think the answer is: 66 numbers between 1 and 200 are divisible by 3. :) That's what I think the answer is.
There are 16 numbers
Exclusively, meaning not including 200 and 500, there are 149 even (divisible by two) numbers between 200 and 500.
There are 33 such numbers.
50 of them.
Not sure!
14 of them
50 of them.