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If x squared y squared equals 25 xy equals 5 prove that x over y plus y over x equals 5 somebody HELP?
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
If y equals one-forth x and x equals -12 then what is y?
x equals -12 and y equals 1/4 of -12, so y = -3.
If y equals 3x and 3x equals 12 then what does y equals?
Well, if 3x equals 12, then x equals 4. And if y equals 3x, then y equals 3 times 4, which is 12. So, y equals 12. Math can be a piece of cake when you break it down like that!
A math problem that equals 1 with 3 variables?
4(x)=12 2+x-y=3 x+y+z=15 4(x)-z+y=1 And in case you didn't figure it out, x is 3, y is 2 and z is 10
If y varies inversely as x and y equals 3 when x equals 6 find the value of x when y equals 18?
3
Geometry math y equals 3x-5 andy equals 6x-2?
x = -1 and y = -8
Y x 2-x?
The expression Y x 2-x can be simplified using the distributive property. First, distribute the Y to both terms inside the parentheses: Y * 2 - Y * x. This simplifies to 2Y - Yx.
If x squared y squared equals 25 xy equals 5 prove that x over y plus y over x equals 5 somebody HELP?
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
What is the answer for y equals x?
x equals y
What algebraic property is 8 equals x and x equals y?
Transitive property: If 8 equals x and x equals y, then 8 equals y.
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
How do you do this math problem y equals x plus 4 and 3y plus x equals 8?
y = x + 43y + x = 8substituting: 3*(x + 4) + x = 8 => 3x + 12 + x = 8 => 4x = -4 => x = -1and then y = x + 4 = -1 + 4 = 3.So the solution is (x, y) = (-1, 3)
How do you write in math symbols x equals any number?
x = Y Im not sure if thats right though :P
What is y equals x plus 2 when x equals -1 and y equals 5?
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
If y equals one-forth x and x equals -12 then what is y?
x equals -12 and y equals 1/4 of -12, so y = -3.
What the results of x plus 2y-2x-y equals x equals?
The result of the equation x + 2y - 2x - y equals x simplifies to y - x.
If x equals 3 and 3 equals y then?
x=y
