Your equations are then x+y = 3
and
xy = -40
Subtracting y from both sides of the first equation we get
x = 3 - y
Substituting this into the second equation we get
xy = -40
(3-y)y = -40
Expanding this we get
-y^2 + 3y = -40
Add 40 to both sides, and multiply by -1 to get
y^2 - 3y - 40 = 0
Factor this to
(y-8)(y+5) = 0
So the zeroes are at y = 8 and y = -5
which means x = -5 and x = 8
-43
-43
LCM of 3 and 7 under 40 is 21
-37
83
no 3 numbers add to equal 10 and multiply to equal 40.
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
20
8
-43
-37
40 + 3 50 - 7 43 x 1
40
you can multiply 281 and 3 you can add 840 and 3
-43
What integers add to -8 and multiply to 15? Sounds like -3 and -5, so: (a - 3b)(a - 5b)
When adding negative integers, you subtract. (2+-1=1) When subtracting negative integers, you add. (2--3=5)