The intersection of the first and second quadrant on a Cartesian plane is null because the first quadrant consists of points with positive x and y coordinates, while the second quadrant consists of points with negative x and positive y coordinates. There are no points that satisfy both conditions simultaneously, resulting in an empty intersection. This is due to the nature of the coordinate system and the definitions of the quadrants based on the signs of the coordinates.
a line divides a plane into three disjoint sets.
The three disjoint sets are:
1.greater than the line.
2.less than the line.
3. the line itself.
in rectangular co-ordinate system,
the Y-axis divides the plane as x>0,y>0
x=o&y>0
x<0&y>0
all the above ones are disjoint.
since intersection of disjoint sets is null set,
therefore,quadrant 1 intersection quadrant 2 is null.
Quadrant 1: (1,5) Quadrant 2: (-2,3) Quadrant 3: (-3,-3) Quadrant 4:(4,-1)
-10.2
The parts on a graph l Quadrant l Quadrant 2 l 1 l ------------------------ l Quadrant l Quadrant 3 l 4 l l
-1
-3
-1
Quadrant 3 Quadrant 4 Quadrant 2 Quadrant 1
Quadrant 1: (1,5) Quadrant 2: (-2,3) Quadrant 3: (-3,-3) Quadrant 4:(4,-1)
-10.2
3
if you have a shape in quadrant 1 of a coordinate plane and another shape in quadrant 2, rotate the shape in quadrant 1 to the right 90 degrees. It, when rotated, the shape in quadrant 1 is congruent to the shape in quadrant 2, then they are rotationally symmetrical.
there is quadrant 1 , quadrant 2 , quadrant 3 , and quadrant 4
If A is in quadrant IV, then A/2 is in quadrant II. Yes, the fact than cos(A) is 0.1 means that A is in quadrant I or IV, but it really is not required in order to answer the question. It is superfluous.
The parts on a graph l Quadrant l Quadrant 2 l 1 l ------------------------ l Quadrant l Quadrant 3 l 4 l l
If you mean the point (7, 9) then it is in the 1st quadrant
-1
There are 4 quadrants on a coordinate plain (grid). The top right is quadrant 1, top left is quadrant 2, bottom left is quadrant 3, and bottom right is quadrant 4.