3, 9, 13, and 39.
The answer respectively is 117. 117 divided by 3 equals 39 and 117 is not divisable by 2. 105, 111, 117.... keep adding 6 so you always have an odd number, and still divisible by 3
No. 5 is not a factor of 117
39, 78, 117, 195, 312 and 936 are divisible by three.
585 is divisible (without remainders) by: 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585.
117 is not a prime number. It is divisible by 3. 3*39=117.
Yes it is.
No, 117 is only divisible by: 1, 3, 9, 13, 39, 117.
3x117=513 or 513/3=117 or 513/117=3
1, 3, 9, 13, 39, 117.
Neither number is prime: 117 is divisible by 3 and 84 is divisible by 2.
117
yes, 351/3=117
939 is evenly divisible by 3 939 is divisible by 8, but not evenly, quotient is 117, remainder is 3
3, 9, 13, and 39.
The answer respectively is 117. 117 divided by 3 equals 39 and 117 is not divisable by 2. 105, 111, 117.... keep adding 6 so you always have an odd number, and still divisible by 3
None of these numbers are prime: 91 is divisible by 7 117 is divisible by 3 84 and 156 are both divisible by 2