No.
Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3:
1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1.
(121 = 40 x 3 + 1)
135
The factors of 363 are: 1, 3, 11, 33, 121, 363
Sure, but not evenly.121/4 = 30.25120 and 124 are both evenly divisible by 4.
242
Yes.
'121'. 121/3 = 40.3333..... Not divisible. 121/5 any number that does not end in '5' or '0' is not divisible by '5' 121/7 = 17 3/7 Not divisible. 121/9 any number whose digits do not sum to nine is not divisible by '9' ; 1+2+1 = 4
121 is not divisible by 6. 121/6 = 20.166666.....7.
121, 242, 363, 484, and an infinite number of other multiples of 121 are divisible by 121.
It is: 135
135
1,089 is divisible by these numbers: 1, 3, 9, 11, 33, 99, 121, 363, 1089.
1, 11, 121
The factors of 363 are: 1, 3, 11, 33, 121, 363
121 is not a prime number. It is divisible by 11.
Sure, but not evenly.121/4 = 30.25120 and 124 are both evenly divisible by 4.
No, it is not, but 121 and 132 are divisible by 11.
Not evenly because 121/8 = 15.125