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Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3:

1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1.

(121 = 40 x 3 + 1)

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โˆ™ 2010-08-14 06:21:42
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Q: Is 121 divisible by 3
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