if you want a mixed number, it is 14 and 1/10 if you want an improper fraction, it is 141/10, because to get it from a mixed number to an improper fraction you multipy the whole number by the denominator, the add that number to the numerator. hope i helped!!!!!!!! ~jaimelefrancais<3
29 - 28 = 1 141 + 1 = 142
I'm not quite sure about that theory, but if all the numbers in the number add up to a number that's dividable by 3, then the number itself would then be divisible by 3. Ex. 141 1+4+1= 6 6 is divisible by 3, so 141 is too. 141/3= 47.
14.5 = 141/2
If you mean two consecutive even whole numbers then they are 140 and 142
Any number which has a finite number of digits is rational.
1.41 as a terminating decimal is a rational number as it can be expressed as one whole number over another: 1.41 = 141/100 All terminating decimals, or decimals that end in repeating digit(s) are rational numbers. --------------------------------------------- If that is an approximation (rounded to 2 decimal places) of √2 = 1.41[421356...] then it irrational.
Any real number is divisible by any other real number
47, 94, 141, 188, 235
141 is a composite because 1, 3, and 47 goes in it
47*3 = 141 therefore not a prime number
Make the divisor (1.41) a whole number and then divide normally. To make the divisor a whole number, the easiest way is to keep multiplying it by 10 until it becomes a whole number; but remember, division is just like a fraction - whatever you do to the denominator (bottom) you must also do to the numerator (top) - so whatever you do to the divisor (the number by which you are dividing) you must do to the dividend (the number into which you are dividing): 0.5 ÷ 1.41 = 50 ÷ 141 (multiply both by 100) = 50/141 ≈ 0.3546
If this is 9 and 6/15, then in fraction mode, it would be 141/15. 1) Multiply the whole number times the denominator (9 x 15 = 135). 2) Add 135 to the numerator (135 + 6 = 141) 3) Place 141 over the denominator (141/15).
One equation that could equal 141 is 70.5 times 2.
I am not sure what you are asking but 141 is divisible by the number 1, itself (141) and certainly by the number 3 so it is not a prime number.
The positive integer factors of 987 are: 1, 3, 7, 21, 47, 141, 329, 987
The positive integer factors of 1269 are: 1, 3, 9, 27, 47, 141, 423, 1269