Yes. put a decimal in the quotient then it will be 10 and when divided by 5 gives 2. Hence answer will be: .2
5 and 31 are prime factors. It is also divisible by 1 and itself, so:155 is divisible by 1, 5, 31, and 155
No, it is divisible by 1, 3, 5, 15.
no, it is divisible by 1, 5, 13, 65
No. It is divisible by 1, 2, 1171, 2342.
7 + 4 + 1 = 12 which is divisible by 3, so 741 is divisible by 3 741 is odd, all multiples of 4 are even, 741 is not divisible by 4 (Alternatively 4 x 2 + 1 x 1 = 9 which is not divisible by 4, so 741 not divisible by 4) All multiples of 5 end with 5 or 0, 741 ends with 1, so 741 not divisible by 5 To be divisible by 6, the number must be divisible by 2 (even) and divisible by 3.741 is odd, so not divisible by 2, so 741 is not divisible by 6 7 + 4 + 1 = 12 which is not divisible by 9, so 741 is not divisible by 9 All multiples of 10 end with 0, 741 ends with 1 so 741 is not divisible by 10 Summary: 741 is divisible by 3, but not by 4, 5, 6, 9 nor 10.
No, because 1 is not evenly divisible by 5. However, all numbers divisible by 5 are divisible by 1.
Between 1 and 2018, 1008 are not divisible by 2.1613 are not divisible by 5.
625 Is divisible by 5
The word is "divisible", not "divisble". And you can't just say that one number is "divisible". You can say that one number is, or is not, divisible by a second number - meaning that when you divide, you get no remainder (if you divide on a calculator, you'll get a whole number, without decimals).
5 and 31 are prime factors. It is also divisible by 1 and itself, so:155 is divisible by 1, 5, 31, and 155
to be divisible by 5 the last digit of the number has to be 0 or 5
5 and 29. That is all and of course 1 and itself.
10 is divisible by 1, 2, 5 & 10
No, it is divisible by 1, 3, 5, 15.
no, it is divisible by 1, 5, 13, 65
No. It is divisible by 1, 2, 1171, 2342.
1,355 is divisible by: 1, 5, 271, 1355.