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Yes, 296 is divisible by 4 because a number is divisible by 4 if the number formed by its last two digits is divisible by 4. In this case, the last two digits of 296 are 96, which is divisible by 4 (96 ÷ 4 = 24). Therefore, 296 is divisible by 4.
2, 3, 4, 6, 8, 12 and 24
Numbers divisible by 24 are those that can be divided by 24 without leaving a remainder. Some examples of numbers divisible by 24 include 24, 48, 72, 96, 120, and so on. This is because 24 is a multiple of 1, 2, 3, 4, 6, 8, 12, and itself, so any number that is a multiple of 24 will also be divisible by these factors.
If a number can be divisible by 2 twice( ei, 48 in half is 24 and 24 can be divided in half. But you can check, without doing any dividing. If the last 2 digits (the tens and ones place digits) is divisible by 4, then the whole number is divisible by 4. How to tell if the last two digits are divisible by 4: add the ones digit to twice the tens digit: if this sum is divisible by 4, then so is the original. This sum can be repeated until a single digit remains. IF this digit is 4 or 8, then the original number is divisible by 4. So if you have a number 975239806723498658859303524, then the last two digits are 24, which is divisible by 4 and the entire number is divisible by 4 (4 + 2×2 = 8 which is 4 or 8, so 24 is divisible by 4). Why this works: Suppose you have a whole number M. Rewrite the number as M = 100*P + Q, where P & Q are whole numbers. Note that Q represents the last two digits, and P is the rest of the number. Now divide this by 4: M/4 = (100*P + Q)/4 = 100*P/4 + Q/4 = 25*P + Q/4. So since P is a whole number, then 25*P is a whole number, and if Q/4 is a whole number, then [M/4 = 25*P + Q/4], which is the sum of two whole numbers is also a whole number, so M is divisible by 4. Let M = 324, so P = 3, and Q = 24. 324 = 100*3 + 24, and 324/4 = 25*3 + 24/4 = 75 + 6 = 81. So 324 is divisible by 4. A number which is divisible by 4 is a multiple of 4