268 is divisible by 2 and 4
the rest of the numbers 268 is not divisible by with a whole number being the dividend.
No - but all the numbers divisible by 10 are divisible by 5 !
If the quotient is an integer then any number whose units digits is not zero (0) is NOT divisible by 10.
No. 15 is divisible by 5.
Yes, since 10 is divisible by 5. Likewise, every number which is divisible by 9 is also divisible by 3.
6 of them or 268/10 = 26.8
In contrast, no prime numbers are divisible by 10. Any prime number is divisible only by itself and 1.
All numbers are divisible by ten but if you are referring to numbers that are divisible by ten and produce a whole number, you are referring to multiples of 10 or any number ending in 0.
Any number ending with 0 is divisible by 10 except for zero itself
No - but all the numbers divisible by 10 are divisible by 5 !
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 10*k, where k is an integer, is evenly divisible.
All numbers divisible by 90 are also divisible by 9 and 10
Every number is divisible by any set of non-zero numbers.Any element of the set of numbers of the form 10*k where k is an integer is evenly divisible.
Any number divisible by 10
If the quotient is an integer then any number whose units digits is not zero (0) is NOT divisible by 10.
All numbers divisible by 10 end in zero and all numbers that end in 0 are divisible by 10. ( I am assuming base 10 notation, of course)
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.