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Yes, 268 is divisible by 2 and 4.

To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2.

To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits

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268 is divisible by 2 and 4

the rest of the numbers 268 is not divisible by with a whole number being the dividend.

Q: Is 268 divisible to any of these numbers 2 3 4 5 6 9 10?

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If the quotient is an integer then any number whose units digits is not zero (0) is NOT divisible by 10.

It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.

Yes, all numbers that are divisible by 5 are also divisible by 10. This is because 10 is a multiple of 5. When we say that a number is divisible by 5, we mean that it can be evenly divided by 5 with no remainder. When we say that a number is divisible by 10, we mean that it can be evenly

No. 15 is divisible by 5.

Any numerical value ending in zero (0) is divisioble by 10. 10,20,30,40,50,60,70,80,90,100, 1000, 1,000,000, 1,000,000,000 are all divisible by '10'. NB THere millions more numbers divisible by '10' , provided they and with a zero(0).

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In contrast, no prime numbers are divisible by 10. Any prime number is divisible only by itself and 1.

All numbers are divisible by ten but if you are referring to numbers that are divisible by ten and produce a whole number, you are referring to multiples of 10 or any number ending in 0.

Any number ending with 0 is divisible by 10 except for zero itself

Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.

Every whole number that ends in 0 is evenly divisible by 10.

Any number divisible by 10

If the quotient is an integer then any number whose units digits is not zero (0) is NOT divisible by 10.

All numbers divisible by 10 end in zero and all numbers that end in 0 are divisible by 10. ( I am assuming base 10 notation, of course)

Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.

Any element of the set of numbers of the form 2345690*k where k is an integer is evenly divisible.

No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.

It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.