To be divisible by 5, the last digit must be 0 or 5.
The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
They are both divisible by 7, so it would be 4/5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, 549 is not divisible by 5.
No. 15 is divisible by 5.
The numbers that are divisible by 5 has 5 or 0 at the end.So,this numbers are divisible by 5.5,10,15,25,555,10000,etc.
28 and 90 are both divisible by 2, as they are both even numbers. Additionally, 28 is divisible by 4 and 7, while 90 is divisible by 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90.
28 is not divisible by 3.
28 is divisible by: 1, 2, 4, 7, 14, 28.
28 is divisible by 1, 2, 4, 7, 14, 28.
28 and its multiples.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
28, 56, 84, and all other multiples of 28 that are factors of other numbers are also divisible by 28.
140 is divisible by these numbers: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
evenly divisible 28 times
They are both divisible by 7, so it would be 4/5.
No.