To be divisible by 5, the last digit must be 0 or 5.
The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
They are both divisible by 7, so it would be 4/5.
No, 549 is not divisible by 5.
No. 15 is divisible by 5.
The numbers that are divisible by 5 has 5 or 0 at the end.So,this numbers are divisible by 5.5,10,15,25,555,10000,etc.
1,2,4,7,14,28 28=2 squared times 7
28 and 90 are both divisible by 2, as they are both even numbers. Additionally, 28 is divisible by 4 and 7, while 90 is divisible by 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90.
28 is not divisible by 3.
28 is divisible by: 1, 2, 4, 7, 14, 28.
28 is divisible by 1, 2, 4, 7, 14, 28.
28 and its multiples.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
28, 56, 84, and all other multiples of 28 that are factors of other numbers are also divisible by 28.
140 is divisible by these numbers: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140.
They are both divisible by 7, so it would be 4/5.
evenly divisible 28 times
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
yes 4x7=28