Yes, the quotient is 99 when you divide by three, but to check for divisibility (by 3 or 9), do this: If the sum of the digits is a multiple of 3 [9], then the number is a multiple of 3 [9]. This only works for 3 and 9. So for 297: 2+9+7 = 18, which is a multiple of 9 and 3, so it is a multiple of 3 (and a multiple of 9, as well; though the question didn't ask for that).
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297 is divisible by (1 x 297) (99 x 3) (33 x 9) (27 x 11)
To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
Little Mathematical trick. If the digits in a number add up to 3 or a multiple of 3 then that number is divisible by 3. If the digits of a number add up to 9 or a multiple of 9 then that number is divisible by 9. 2 + 9 + 7 = 18 ........which is a multiple of both 3 and 9. Lets start with 3 297 ÷ 3 = 99 (9 + 9 = 18 so we can divide again by 3 and/or9) 99 ÷ 3 = 33 (3 + 3 = 6 so we can divide by 3) 33 ÷ 3 = 11 (11 is a prime number so no more factors. The prime factors of 297 are 33 and 11. The factors of 297 are : 297, 99, 33, 27, 11, 9, 3 and 1
1/3 of 297 = 297/3 = 99
As a product of its prime factors: 3*3*3*11 = 297 or as 1*1*1*297 = 297