Yes, the quotient is 99 when you divide by three, but to check for divisibility (by 3 or 9), do this: If the sum of the digits is a multiple of 3 [9], then the number is a multiple of 3 [9]. This only works for 3 and 9. So for 297: 2+9+7 = 18, which is a multiple of 9 and 3, so it is a multiple of 3 (and a multiple of 9, as well; though the question didn't ask for that).
297 is divisible by (1 x 297) (99 x 3) (33 x 9) (27 x 11)
Little Mathematical trick. If the digits in a number add up to 3 or a multiple of 3 then that number is divisible by 3. If the digits of a number add up to 9 or a multiple of 9 then that number is divisible by 9. 2 + 9 + 7 = 18 ........which is a multiple of both 3 and 9. Lets start with 3 297 ÷ 3 = 99 (9 + 9 = 18 so we can divide again by 3 and/or9) 99 ÷ 3 = 33 (3 + 3 = 6 so we can divide by 3) 33 ÷ 3 = 11 (11 is a prime number so no more factors. The prime factors of 297 are 33 and 11. The factors of 297 are : 297, 99, 33, 27, 11, 9, 3 and 1
1/3 of 297 = 297/3 = 99
As a product of its prime factors: 3*3*3*11 = 297 or as 1*1*1*297 = 297
Every number is divisible by any non-zero number such as 891. Any element of the set of numbers of the form 891*k, where k is an integer, is evenly divisible.
297 is divisible by (1 x 297) (99 x 3) (33 x 9) (27 x 11)
Yes, it is. 891 divided by 3 is 297. 297 is a whole number, so 891 can be said to be divisible by three.
No.
There are 17 ranging from 110 to 297
The digits of this odd number sum to 18, which is divisible by 3 so 297 is divisible by 3: 3 x 99; 99 is 11 x 9 so the answer to your question would be 3, 9 and 11, but 9 is not prime so there is no answer in prime factors.
Little Mathematical trick. If the digits in a number add up to 3 or a multiple of 3 then that number is divisible by 3. If the digits of a number add up to 9 or a multiple of 9 then that number is divisible by 9. 2 + 9 + 7 = 18 ........which is a multiple of both 3 and 9. Lets start with 3 297 ÷ 3 = 99 (9 + 9 = 18 so we can divide again by 3 and/or9) 99 ÷ 3 = 33 (3 + 3 = 6 so we can divide by 3) 33 ÷ 3 = 11 (11 is a prime number so no more factors. The prime factors of 297 are 33 and 11. The factors of 297 are : 297, 99, 33, 27, 11, 9, 3 and 1
All multiples of 891, which is an infinite number.
Yes. 891 is divisible by: 1, 3, 9, 11, 27, 33, 81, 99, 297, 891.
No. It is only divisible by these numbers: 1 3 7 9 11 21 27 33 63 77 99 189 231 297 693 and 2079.
1/3 of 297 = 297/3 = 99
As a product of its prime factors: 3*3*3*11 = 297 or as 1*1*1*297 = 297
-297