3x + 2y = 8
2y=8-3x
y=4-1.5x
A quadratic has x^2
This is the equation of a line with negative slope.
(3, 2)
-7x - 2y = -3
2y = 4x + 4y = 2x + 2
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
Yes.
This means that 2y - 3 = 2y + 4 which is not possible.
No 2y-3 is not equals y plus 2AND how old are u?
Implicit: x2 + 2y = 5 Explicit : y = (5 - x2)/2
(3, 2)
2y+26 = 28 2y = 28-26 2y = 2 y = 1
2y(x+2)=
-2y=x+8 is the answer
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
Generally, function values are Y values, so.......... 6X + 2Y = 24 subtract 6X from each side 2Y = - 6X + 24 divide both the integers on the right by 2 Y = - 3X + 12 -------------------------the function
Exactly (2y + 4) .
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?