113
70.625
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, 549 is not divisible by 5.
Yes, all numbers that are divisible by 5 are also divisible by 10. This is because 10 is a multiple of 5. When we say that a number is divisible by 5, we mean that it can be evenly divided by 5 with no remainder. When we say that a number is divisible by 10, we mean that it can be evenly
5, 113.
No, the number 566 is not evenly divisible by 5. Only numbers that end in 5 or 0 are evenly divisible by 5. If you subtract 1 from 566 you then have a number that is evenly divisible by 5, which is 565. 565/5 = 113.
All number that are completely divisible by 10 (with no remainder) end in 0 (zero). Dividing 565 by 10 yields 56 with a remainder of 5 (or 56.5 or 56½) - so - NO - 565 is NOT divisible by 10.
No, 565 divided by 6 is 94.17
6
if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565
No. 59,890 is divisible by these numbers: 1, 2, 5, 10, 53, 106, 113, 226, 265, 530, 565, 1130, 5989, 11978, 29945, 59890.
113
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
565 = 5 x 113
Factors of 115: 1, 5, 23, 115Factors of 235: 1, 5, 47, 235Factors of 565: 1, 5, 113, 565GCF (115, 235, 565) = 5
As a product of its prime factors: 5*113 = 565