113
70.625
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, 549 is not divisible by 5.
No. 15 is divisible by 5.
5, 113.
No, the number 566 is not evenly divisible by 5. Only numbers that end in 5 or 0 are evenly divisible by 5. If you subtract 1 from 566 you then have a number that is evenly divisible by 5, which is 565. 565/5 = 113.
All number that are completely divisible by 10 (with no remainder) end in 0 (zero). Dividing 565 by 10 yields 56 with a remainder of 5 (or 56.5 or 56½) - so - NO - 565 is NOT divisible by 10.
No, 565 divided by 6 is 94.17
6
if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565
No. 59,890 is divisible by these numbers: 1, 2, 5, 10, 53, 106, 113, 226, 265, 530, 565, 1130, 5989, 11978, 29945, 59890.
113
All numbers are divisible by 2145. Any element of the set of numbers of the form 2145*k where k is an integer is evenly divisible.
565 = 5 x 113
Factors of 115: 1, 5, 23, 115Factors of 235: 1, 5, 47, 235Factors of 565: 1, 5, 113, 565GCF (115, 235, 565) = 5
As a product of its prime factors: 5*113 = 565