Yes but it will have a remainder of 5
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To determine what numbers 585 is divisible by, we need to find its factors. 585 is divisible by 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, and 585 itself. This means that 585 can be divided evenly by any of these numbers without leaving a remainder.
No. Al multiples of 6 are even but 585 is odd so it cannot be a multiple of 6, and hence cannot be divisible by 6.
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
4095 / 7 = 585 4095 / 13 = 315 4095 / 17 = 240.88235